
回答:
说明:
#“给出一条斜率为m的线然后是一条线的斜率”#
#“垂直于它”#
#m_(颜色(红色) “垂直”)= - 1 / M#
#y = -1 / 3x + 1“处于斜率截距形式”#
#•颜色(白色)(X)Y = mx + b中#
#“其中m是斜率,b是y截距”#
#rArry = -1 / 3x + 1“有斜率”m = -1 / 3#
#rArrm_(颜色(红色) “垂直”)= - 1 /( - 1/3)= 3#
#rArry = 3x + blarr“partial equation”#
#“找到b替代”(2,7)“进入等式”#
#7 = 6 + brArrb = 1#
#rArry = 3x + 1larrcolor(红色)“斜率截距形式”#