我该如何解决这个问题?
由于X与三角形ABC的三个顶点等距(5m),X是DeltaABC的圆周。因此angleBXC = 2 * angleBAC现在BC ^ 2 = XB ^ 2 + XC ^ 2-2XB * XC * cosangleBXC => BC ^ 2 = 5 ^ 2 + 5 ^ 2-2 * 5 ^ 2 * cos / _BXC => BC ^ 2 = 2 * 5 ^ 2(1-cos(2 * / _ BAC)=> BC ^ 2 = 2 * 5 ^ 2 * 2sin ^ 2 / _BAC => BC = 10sin / _BAC = 10sin80 ^ @ = 9.84m类似地AB = 10sin/_ACB=10sin40^@=6.42m和AC = 10sin/_ABC=10*sin60^@=8.66m