回答:
说明:
一般来说:
#a_x,a_y,a_z xx b_x,b_y,b_z = abs((a_y,a_z),(b_y,b_z)),abs((a_z,a_z),(b_z,b_x)),abs( (a_x,a_y),(b_x,b_y))#
所以:
#1,2,1 xx 3,1,-5#
#= abs((2,1),(1,-5)),abs((1,1),( - 5,3)),abs((1,2),(3,1)) #
#= (2*-5)-(1*1), (1*3)-(1*-5), (1*1)-(2*3)#
#= -10-1, 3+5, 1-6#
#= -11, 8, -5#