在2秒内从(-1,7,2)到(-3,4,7)的物体的速度是多少?

在2秒内从(-1,7,2)到(-3,4,7)的物体的速度是多少?
Anonim

回答:

#v = sqrt 10#

说明:

#“两点之间的距离为:”#

#x = sqrt(Delta x ^ 2 + Delta y ^ 2 + Delta z ^ 2#

#Delta x = x_2-x_1 = -3 + 1 = -2#

#Delta y = y_2-y_1 = 4-7 = -3#

#Delta z = z_2-z_1 = -3-2#=-5

#X = SQRT(( - 2)^2 (-3)^ 2 +( - 5)^ 2)#

#x = sqrt(4 + 9 + 25)#

#X = sqrt40#

#V = X / T#

#v = sqrt 40/2#

#v = sqrt(4 * 10)/ 2 = 2 * sqrt 10/2#

#v = sqrt 10#