你如何写有理表达式x ^ 2 /((x-1)(x + 2))的部分分数分解?

你如何写有理表达式x ^ 2 /((x-1)(x + 2))的部分分数分解?
Anonim

回答:

#的x ^ 2 /((X-1)(X + 2))= 1 /(3(X-1)) - 4 /(3(X + 2))#

说明:

我们需要根据每个因素来写这些。

#的x ^ 2 /((X-1)(X + 2))= A /(X-1)+ B /(X + 2)#

#x的^ 2 = A(X + 2)+ B(X-1)#

投入 #X = -2#:

#( - 2)^ 2 = A(-2 + 2)+ B(-2-1)#

#4 = -3B#

#B = -4 / 3#

投入 #X = 1#:

#1 ^ 2 = A(1 + 2)+ B(1-1)#

#1 = 3A#

#A = 1/3号

#的x ^ 2 /((X-1)(X + 2))=(1/3)/(X-1)+( - 4/3)/(X + 2)#

#COLOR(白色)(X ^ 2 /((X-1)(X + 2)))= 1 /(3(X-1)) - 4 /(3(X + 2))#

回答:

#1 + 1/3 * 1 /(X-1)-4 / 3 * 1 /(X + 2)#

说明:

#x的^ 2 / (X-1)(X + 2)#

=#(X-1)(X + 2)+ X ^ 2-(X-1)(X + 2) / (X-1)(X + 2)#

=#1 - (X-1)(X + 2)-x ^ 2 / (X-1)(X + 2)#

=#1-(X-2)/ (X-1)(X + 2)#

现在,我将分数分解为基本分数,

#(X-2)/ (X-1)(X + 2) = A /(X-1)+ B /(X + 2)#

扩大分母后,

#A *(X + 2)+ B *(X-1)= X-2#

#X = -2#, #-3B = -4#所以 #B = 4/3#

#X = 1#, #3A = -1#所以 #A = -1 / 3#

因此,

#(X-2)/ (X-1)(X + 2) = - 1/3 * 1 /(X-1)+ 4/3 * 1 /(X + 2)#

从而,

#x的^ 2 / (X-1)(X + 2)#

=#1-(X-2)/ (X-1)(X + 2)#

=#1 + 1/3 * 1 /(X-1)-4 / 3 * 1 /(X + 2)#