回答:
#罪^ 2xcos ^ 2×=(1-COS(4×))/ 8#
说明:
#罪^ 2×=(1-COS(2×))/ 2#
#COS ^ 2×=(1个+ COS(2×))/ 2#
#罪^ 2xcos ^ 2×=((1 + cos(2×))(1-COS(2×)))/ 4 =(1-COS ^ 2(2×))/ 4#
#COS ^ 2(2×)=(1个+ COS(4×))/ 2#
#(1-(1个+ COS(4×))/ 2)/ 4 =(2-(1个+ COS(4×)))/ 8 =(1-COS(4×))/ 8#