Ax + By = 7和Ax-By = 9的图在(4,-1)处相交。 A和B的价值是多少?

Ax + By = 7和Ax-By = 9的图在(4,-1)处相交。 A和B的价值是多少?
Anonim

回答:

#A = 2#

#B = 1#

说明:

鉴于:

#Ax + By = 7“1”#

#Ax - By = 9“2”#

在两个方程式中,将4替换为x,将y替换为-1:

#4A - B = 7“1.1”#

#4A + B = 9“2.1”#

将等式1.1添加到等式2.1:

#4A + 4A - B + B = 7 + 9#

结合类似的术语:

#8A = 16#

#A = 2#

在等式2.1中用A代替2,然后求解B:

#4(2)+ B = 9#

#B = 1#

校验:

#2(4) + 1(-1) = 7#

#2(4) - 1(-1) = 9

#7 = 7#

#9 = 9#

这检查。