你如何验证身份3sec ^ 2thetatan ^ 2theta + 1 = sec ^ 6theta-tan ^ 6theta？

回答：

见下文

说明：

#3秒^ 2thetatan ^的2θ+ 1 =秒^ 6theta坦^ 6theta#

右边#=秒^ 6theta坦^ 6theta#

#=（秒^的2θ）^ 3-（黄褐色^的2θ）^ 3# - >使用两个立方体公式的差异

#=（sec ^ 2theta-tan ^ 2theta）（sec ^ 4theta + sec ^ 2thetatan ^ 2theta + tan ^ 4theta）#

#= 1 *（sec ^ 4theta + sec ^ 2thetatan ^ 2theta + tan ^ 4theta）#

#=秒^ 4theta +秒^ 2thetatan ^的2θ+黄褐色^ 4theta#

#= sec ^ 2theta sec ^ 2 theta + sec ^ 2thetatan ^ 2theta + tan ^ 2theta tan ^ 2 theta#

#= sec ^ 2theta（tan ^ 2theta + 1）+ sec ^ 2thetatan ^ 2theta + tan ^ 2theta（sec ^ 2theta-1）#

#=秒^ 2thetatan ^的2θ+秒^的2θ+秒^ 2thetatan ^的2θ+秒^ 2thetatan ^ 2thetatan ^的2θ#

#=秒^ 2thetatan ^的2θ+秒^ 2thetatan ^的2θ+秒^ 2thetatan ^的2θ+秒^ 2thetatan ^的2θ#

#= 3秒^ 2thetatan ^ 2theta + 1#

#=# 左边